Both the Rankine as well as the Euler formula are used for buckling calculation, however, the accuracy of the buckling calculation results depends upon the proper application of the Rankine and Euler formulas for metric steel columns or strut.

**What is a Column or Strut?**

Any machine member, subjected to the axial compressive loading is called a strut and the vertical strut is called column

The columns are generally categorized in two types: **short** columns and **long** columns. The one with length less than eight times the diameter (or approximate diameter) is called short column and the one with length more than thirty times the diameter (or approximate diameter) is called long column.

Ideally, the columns should fail by crushing or compressive

stress and it normally happens for the short columns, however, the long columns, most of the times, failure occurs by buckling.

**Euler’s Buckling Formula **

To get the correct results, this formula should only be applied for the long columns. The buckling load calculated by the Euler formula is given by:

**Fbe** = (C*Π^{2}*E*I)/L^{2}…………..**Eqn.1.1**

** **

Where,

Fbe = Buckling force calculated by the Euler’s formula.

C = End fixity coefficient to be selected based on the end conditions of the column.

E = Modulus of elasticity

I = area moment of inertia of the cross section of the column

L = length of the column

The end fixity constant (C) used in the above **Eqn.1.1** to be selected as below:

- For the column with both end hinged –
**1** - For the column with both end fixed –
**4** - For the column with one end fixed and other end hinged –
**2** - For the column with one end fixed and other end free –
**0.25**

Please note that out of the two area moment of inertia Ixx and Iyy, the least one has to be considered for the above equation. The things will be clearer, once you will go through the next example.

**Example: ** Find out the buckling stress of a 4 meter long both ends fixed column, which has rectangular cross section of size 200mm X 100 mm. Assume the modulus of elasticity as 100 kN/mm^{2}.

**Solution: **

Ixx = (100*200^{3})/12 = 66666666.67 mm^{3}

Iyy = (200*100^{3})/12 = 16666666.67mm^{3}

Fbe = (4* 3.14^{2}*100*16666666.67)/4000^{2} = 4108.167 k**N**

** **

**Rankine’s Buckling Formula for Columns**

The Euler’s formula is ideal only for the long columns. To eliminate this limitation of the Euler’s formula, Prof. Rankine came out with the following empirical formula:

1/Fbr = 1/Fc + 1/Fbe ……………**Eqn.1.2**

** **Where,

Fbr = buckling load calculated using Rankine’s formula

Fc = ultimate crushing load on the column = **σuc * A**

σuc** = **ultimate compressive stress for the column material

A = area of the cross section of the column

Fbe = buckling load calculated using Euler’s formula

**Conclusion**

The buckling calculation is done using the Rankine and Euler Formulas for Metric Steel Columns or strut. The Euler formula is ideal for long column. The Rankine formula is a more general formula and can be used for both the long as well as the short column.

### Shibashis Ghosh

Disclaimer: I work for Altair. mechGuru.com is my personal blog. Although i have tried to put my neutral opinion while writing about different competitor's technologies, still i would like you to read the articles by keeping my background in mind.

#### Latest posts by Shibashis Ghosh (see all)

- 3D Printing Simulation Software – Are They Capable Enough? - July 16, 2017
- Do Value Engineering Upfront, Right at Design Stage - November 22, 2015
- HPDC vs LPDC - November 7, 2015

sir how we calculate the weight of per props while loaing

sir how to calculate EI in column and strut

EI is irrelevant for a strut. It is the cross section area ‘A’ that is the useful parameter for it. For a Column, EI to be considered to evaluate the critical load is the lowest of all the possible values. If it is a circular cross section, then there is only one I value.